By Barnabas Hughes
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Extra info for Fibonacci’s De Practica Geometrie
And thus we have 9 rods, 2 feet, and 72 10 inches for 71 of 66 rods. All of this is very useful as will be shown in its own place. 1). 1 Measuring Areas of Rectangular Fields COMMENTARY A set of twenty-five solved problems and twelve theorems comprise the two parts or Methods of Chapter 1. In Part I all of the problems focus on finding areas of fields given dimensions in one, two, and/or three different units of measurement, which make the multiplication complex. Fibonacci’s method for multiplication most probably reflects the method common to Pisa, if not much of the Mediterranean world.
11  Thus strive to proceed along a similar way that seems better to you according 7 to the number of inches. Add therefore 12 83 deniers to the 9 soldi less 13 of one denier to make 16 soldi less 43 of one denier. Add to this the product of feet by feet, namely 4 by 5, and the 20 denier become 17 soldi and 14 7 deniers. To this add as above the cross product of half the feet by the rods, and of rods by rods. You will have in sum 8 staria, 10 panes, 7 soldi, and 14 1 deniers.
Likewise multiply 4 feet, namely 2 soldi, by 43 rods to get 86 soldi, namely 5 panes and 1 1 2 3 soldi. Likewise multiply 5 feet, namely 2 2 soldi, by 26 rods to get 65 soldi. Likewise multiply 4 feet by 5 feet to get 20 deniers. By combining these four products into one you have in sum 17 staria, 8 panes, 8 soldi, and 8 deniers.  If you wish to multiply 28 rods, 1 foot, and 7 inches by 53 rods, 5 feet, and 12 inches, first multiply the 28 rods and 1 foot by 53 rods and 5 feet to get 22 staria, 11 panes, 11 soldi, and 5 deniers.
Fibonacci’s De Practica Geometrie by Barnabas Hughes