By Barnabas Hughes

ISBN-10: 0387729305

ISBN-13: 9780387729305

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Extra info for Fibonacci’s De Practica Geometrie

Example text

And thus we have 9 rods, 2 feet, and 72 10 inches for 71 of 66 rods. All of this is very useful as will be shown in its own place. 1). 1 Measuring Areas of Rectangular Fields COMMENTARY A set of twenty-five solved problems and twelve theorems comprise the two parts or Methods of Chapter 1. In Part I all of the problems focus on finding areas of fields given dimensions in one, two, and/or three different units of measurement, which make the multiplication complex. Fibonacci’s method for multiplication most probably reflects the method common to Pisa, if not much of the Mediterranean world.

11 [25] Thus strive to proceed along a similar way that seems better to you according 7 to the number of inches. Add therefore 12 83 deniers to the 9 soldi less 13 of one denier to make 16 soldi less 43 of one denier. Add to this the product of feet by feet, namely 4 by 5, and the 20 denier become 17 soldi and 14 7 deniers. To this add as above the cross product of half the feet by the rods, and of rods by rods. You will have in sum 8 staria, 10 panes, 7 soldi, and 14 1 deniers.

Likewise multiply 4 feet, namely 2 soldi, by 43 rods to get 86 soldi, namely 5 panes and 1 1 2 3 soldi. Likewise multiply 5 feet, namely 2 2 soldi, by 26 rods to get 65 soldi. Likewise multiply 4 feet by 5 feet to get 20 deniers. By combining these four products into one you have in sum 17 staria, 8 panes, 8 soldi, and 8 deniers. [16] If you wish to multiply 28 rods, 1 foot, and 7 inches by 53 rods, 5 feet, and 12 inches, first multiply the 28 rods and 1 foot by 53 rods and 5 feet to get 22 staria, 11 panes, 11 soldi, and 5 deniers.

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Fibonacci’s De Practica Geometrie by Barnabas Hughes

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